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    class Dog {
        bark(){
            return 'barking'
        }
    }
    const fido = new Dog()
    fido

• fido doesn't have a bark method directly on it.
• Instead, fido.__proto__ (or Object.getPrototypeOf(fido)) points to Dog.prototype, where bark lives.
• So fido.bark() works because JavaScript looks up the prototype chain and finds it there.

⛓️ Think of It Like a Chain When you call a method on an object:

• JS looks on the object itself.
• If it doesn't find it, it goes to the object's prototype.
• If still not found, it keeps going up the chain until it hits null.

So you're not seeing methods directly on instances because they're not there — they're on the prototype.